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IBM C9050-042 Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| Debugging and Optimization | - Debugging techniques
|
| PL/I Language Fundamentals | - Basic syntax and program structure
|
| Program Control and Logic | - Control statements
|
| File Handling and Data Management | - Sequential and indexed file processing
|
| IBM Enterprise PL/I Features | - Enterprise extensions
|
IBM Developing with IBM Enterprise PL/I Sample Questions:
1. Given the following code, what measure will NOT improve stability?
S1: PROC (X,Y,Z);
DCL X DEC FIXED (5);
DCL Y PlC '99999';
DCL Z DEC FIXED (5);
Z = X + Y;
END;
A) Check result overflow.
B) Check Y for valid numeric data.
C) Check Z for valid packed data.
D) Check X for valid packed data.
2. Given the following code, which call will pass a dummy argument?
PROG: PROC OPTIONS(MAIN);
DCL SUM01 DEC FIXED(5,0) INIT (7);
DCL SUM02 DEC FIXED(9,0) INIT (999);
CALL SUBA(SUM01,
SUM02);
CALL SUSB(SUM01,
SUM02);
CALL SUBC(SUM01,
SUM02);
CALL SUBD(SUM01,
SUM02);
SUBA PROC( PRM1,
PRM2);
DCL PRM1 DEC FIXED (5,0) BYVALUE,
PRM2 DEC FIXED (9,0);
END SUBA;
SUBB:PROC( PRM1,
PRM2);
DCL PRM1 DEC FIXED (5,0),
PRM2 DEC FIXED (9,0);
END SUBD;
SUBC: PROC( PRM 1,
PRM2);
DCL PRM1 BIN FIXED (15,0),
PRM2 DEC FIXED (9,0);
END SUBC;
SUBD:PROC( PRM 1,
PRM2);
DCL PRM1 DEC FIXED(5,0) BYADDR,
PRM2 DEC FIXED (9,0) SYADDP;
END SUBD;
END PROG;
A) CaII to SUBB
B) CaII to SUBD
C) CaII to SUBC
D) Call to SUBA
3. In a multithreading environment, when can a race condition occur between two threads?
A) When they cause a deadlock
B) When the threads have the same priority
C) When they operate synchronously
D) When they periorm an operation on same memory area
4. What is a program specification document?
A) A description of how the program does its work
B) The history of changes of the program and how it was used
C) The pseudocode of the program
D) A description of what the program does and how it can be used
5. Given the following (incomplete) code, how is Q to be declared in order to allocate X in A?
DCL A AREA;
DCL Q ...
DCL X FIXED BIN (31) BASED (Q);
ALLOCATE X;
A) ... OFFSET(A);
B) ... BASED(A);
C) ... POINTER;
D) ... OFFSET;
Solutions:
| Question # 1 Answer: C | Question # 2 Answer: C | Question # 3 Answer: D | Question # 4 Answer: D | Question # 5 Answer: A |







